SOLUTION: Find the first 5 terms of the sequence an=2n^2-8

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Question 744462: Find the first 5 terms of the sequence an=2n^2-8
Answer by sachi(548) About Me  (Show Source):
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an=2n^2-8
so a1=2*1^2-8=-6
a2=2*2^2-8=0
a3=2*3^2-8=10
a4=2*4^2-8=24
a5=2*5^2-8=42