Question 743766:
find 2 consecutive odd integer such that three-forths of the large number is 5 more than one-forth of the smaller number.find the numbers Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! LET X & X+2 BE THE 2 INTEGERS.
.75(X+2)=.25X+5
.75X+1.5=.25X+5
.75X-.25X=5-1.5
.50X=3.5
X=3.5/.50
X=7 ANS. FOR THE SMALLER INTEGER.
7+2=9 ANS. FOR THE LARGER INTEGER.
PROOF:
.75*9=.25*7+5
6.75=1.75+5
6.75=6.75