SOLUTION: Find the equation of the tangent line for f(x)=3x^2-x at the given point (-2,14)
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Question 743739
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Find the equation of the tangent line for f(x)=3x^2-x at the given point (-2,14)
Answer by
tommyt3rd(5050)
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f' = 6x-1
f'(-2)=6(-2)-1=-13
so m=-13
y-b=m(x-a)
y-14=-13(x--2)
y-14=-13(x+2)
:)