SOLUTION: Find four consecutive even integers such that twice the third integer subtracted from five times the first equals 18 more than the sum of the second and the fourth integer.

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Question 743729: Find four consecutive even integers such that twice the third integer subtracted from five times the first equals 18 more than the sum of the second and the fourth integer.
Answer by josgarithmetic(39626) About Me  (Show Source):
You can put this solution on YOUR website!
Four consecutive even integers are
2n
2n+2
2n+4
2n+6

5%282n%29-2%2A%282n%2B4%29------twice the third integer subtracted from five times the first

18%2B%282n%2B2%29%2B%282n%2B6%29--------18 more than the sum of the second and the fourth integer

highlight%285%282n%29-2%2A%282n%2B4%29=18%2B%282n%2B2%29%2B%282n%2B6%29%29
Simplify and solve for n.
Use n found to compute each of the integers.