SOLUTION: I need some help with this question
-4 1/5x2 + 1 2/5x - 2 4/5 = 0
Here are my options. I can't seem to get it right.
A) x = {1 +- i[SQRT(23)]}/6
B) x = {-1 +- i[SQRT(10)
Question 743616: I need some help with this question
-4 1/5x2 + 1 2/5x - 2 4/5 = 0
Here are my options. I can't seem to get it right.
A) x = {1 +- i[SQRT(23)]}/6
B) x = {-1 +- i[SQRT(10)]} / 6
C) x = {1 +- [SQRT(23)]} /-6
D) x = 1 +- 5/2 x^2
E) x = -1 +- 2/5 x^2
F) x = 2 +- 20 x^2 Answer by Edwin McCravy(20060) (Show Source):
x² + x - = 0
Change the mixed fractions to improper fractions:
x² + x - = 0
Clear of fractions by multiplying every term through by 5
-21x² + 7x - 14 = 0
Divide through by -7, (negative so the leading term will be
positive):
3x² - x + 2 = 0
That doesn't factor so we use the quadratic formula:
x =
with a = 3, b = -1, c = 2
x =
x =
x =
x =
x =
Edwin
