SOLUTION: The length of a rectangle is 4yd longer than its width.
If the perimeter of the rectangle is 28yd , find its area.
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-> SOLUTION: The length of a rectangle is 4yd longer than its width.
If the perimeter of the rectangle is 28yd , find its area.
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Question 743309: The length of a rectangle is 4yd longer than its width.
If the perimeter of the rectangle is 28yd , find its area. Answer by tommyt3rd(5050) (Show Source):
You can put this solution on YOUR website! l=w+4
P=2(l+w)=28
or l+w=14 and so l=14-w
which leads us to
w+4=14-w
w+w+4-4=14-4-w+w
2w=10
and w=5
therefore l=5+4=9
and that means A=lw=(9)(5)=45 square yards
