Drop the 72. This is an average problem:  avg = sum/(# of numbers).  Call the final exam grade x since it's unknown.
AVG = 90 = (86+90+87+92+88+94+x)/7
90 = (893+x)/7
630=537+x
93=x
If the question asked what was the needed score to earn at least an A-, then the answer would be:
93 <= x
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