Question 74309: Factor completely. Remember that you can check bymultiplying. If a polynomial is prime state this.
1. x^2+6x+5
2. x^2+7x+10
3. y^2+11y+28
4. a^2-11a+30
5. x^2+5x+4
6. z^2-8z+7
7. x^2-8x+15
8. y^2-11y+10
9. x^2+x-42
Answer by funmath(2933)   (Show Source):
You can put this solution on YOUR website! Factor completely. Remember that you can check bymultiplying. If a polynomial is prime state this.
:
If this is all of your homework, please look at the first couple and try the rest before looking at my work. You aren't going to get the hang of factoring without a lot of practice.
:
1. x^2+6x+5
(x___)(x___)
Fill the blanks with two integers that multiply to give you the last integer, +5, but add to give you the middle coefficient, +6.
1*5=5 and 1+5=6
(x+1)(x+5)
:
2. x^2+7x+10
(x___)(x___)
Two integers that multiply to give you +10, but add to give you a +7:
2*5=10 2+5=7
(x+2)(x+5)
:
3. y^2+11y+28
(y___)(y___)
Two integers that multiply to give you +28, but add to give you +11:
4*7=28 4+7=11
(y+4)(Y+7)
:
4. a^2-11a+30
(a__)(a__)
Two intgers that multiply to give you +30, but add to give you -11:
-5*-6=30 -5+(-6)=-11
(a-5)(a-6)
:
5. x^2+5x+4
(x__)(x__)
Two integers that multiply to give you +4, but add to give you +5:
1*4=4 1+4=5
(x+1)(x+4)
:
6. z^2-8z+7
(z___)(z___)
Two integers that multiply to give you +7, but add to give you -8:
-1*-7=7 -1+(-7)=-8
(z-1)(z-7)
:
7. x^2-8x+15
(x___)(x__)
Two integers that multiply to give you +15, but add to give you -8:
-3*-5=15 -3+(-5)=-8
(x-3)(x-5)
:
8. y^2-11y+10
(y__)(y__)
Two integers that multiply to give +10, but add to give -11:
-1*-10=10 -1+(-10)=-11
(y-1)(y-10)
:
9. x^2+x-42
(x__)(x__)
Two numbers that multiply to give you -42, but add to give you +1:
7*-6=-42 7+(-6)=1
(x+7)(x-6)
Happy Calculating!!!!
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