SOLUTION: find an interval for theta for which the graph is traced only once r=2sin(3theta/2)
a-0<=theta<=pie/3
b-0<=theta<=pie
c-0<=theta<=4pie
d-0<=theta<=4pie/3
e- -2pie<=theta<=2pie
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-> SOLUTION: find an interval for theta for which the graph is traced only once r=2sin(3theta/2)
a-0<=theta<=pie/3
b-0<=theta<=pie
c-0<=theta<=4pie
d-0<=theta<=4pie/3
e- -2pie<=theta<=2pie
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Question 742970: find an interval for theta for which the graph is traced only once r=2sin(3theta/2)
a-0<=theta<=pie/3
b-0<=theta<=pie
c-0<=theta<=4pie
d-0<=theta<=4pie/3
e- -2pie<=theta<=2pie Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find an interval for theta for which the graph is traced only once
r=2sin(3theta/2) = 2sin((3/2)theta)
Form: r = asin(bx) + c
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That would be one period.
Period = (2pi/b) = (2pi/(3/2)) = (4/3)pi
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Answer: "d"
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Cheers,
Stan H.
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a-0<=theta<=pie/3
b-0<=theta<=pie
c-0<=theta<=4pie
d-0<=theta<=4pie/3
e- -2pie<=theta<=2pie
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