A committe of 5 people is to be selected from four males and six females. What is the probability that the committee created will contain at least 3 males?
To succeed we must select committees with
3 males and 2 females or with 4 males and 1 female
The number of ways to select 3 males and 2 females is C(4,3)C(6,2) ways.
The number of ways to select 4 males and 1 females is C(4,4)C(6,1) ways
We add those to find the numerator of the desired probability
The number of ways to select any committee of 5 is "10 people Choose 5",
which is C(10,5) ways.
That's the denominator of the desired probability.
Desired probability = 
= 
Edwin
