Question 742157: How do you find the solutions for: sin^2(x)=sin(x)+2
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! How do you find the solutions for: sin^2(x)=sin(x)+2
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sin^2(x) - sin(x) - 2 = 0
sub for sin(x)
u^2 - u - 2 = 0
(u - 2)*(u + 1) = 0
u = 2 --> sin(x) = 2 (no real number solution)
u = -1 --> sin(x) = -1
x = pi + 2n*pi, n = 0, 1, 2, 3...
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