SOLUTION: Find the remaining zeros of the following polynomial given that P(i)=0. P(x) = x^4 -8x^3 +14x^2 -8x +13 I know that -i is the conjugate so (x+i)(x-i) = (x^2+1). I am stuck with

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the remaining zeros of the following polynomial given that P(i)=0. P(x) = x^4 -8x^3 +14x^2 -8x +13 I know that -i is the conjugate so (x+i)(x-i) = (x^2+1). I am stuck with       Log On


   

Question 742143: Find the remaining zeros of the following polynomial given that P(i)=0.
P(x) = x^4 -8x^3 +14x^2 -8x +13
I know that -i is the conjugate so (x+i)(x-i) = (x^2+1). I am stuck with how to break down the polynomial. Sythetic division leaves a remainer. I also know I need to get this into quadradic from so I can use the formula.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the remaining zeros of the following polynomial given that P(i)=0.
P(x) = x^4 -8x^3 +14x^2 -8x +13
I know that -i is the conjugate so (x+i)(x-i) = (x^2+1). I am stuck with how to break down the polynomial.
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The problem is that "i" is not a root of P(x). You can see that
if you substitute "i" for "x".
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Cheers,
Stan H.
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