SOLUTION: 3/(4c+2)-(c-4)/(2c^2+c)-5/6c

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Question 74213: 3/(4c+2)-(c-4)/(2c^2+c)-5/6c
Answer by rmromero(383) About Me  (Show Source):
You can put this solution on YOUR website!


          3         (c-4)       5

        ______ -  __________ - ____

        4c + 2     2c^2 + c     6c  



Factor the denominator



          3          c - 4       5

        _______ -  __________ - ____

        2(2c+1)      c(2c+1)     6c  





Find LCD = 6c(2c+1)



            3     6c(2c+1)       c - 4       6c(2c+1)    5     6c(2c+1)

        _______ * ________  -  __________ * _________ - ____ * _________

        2(2c+1)   6c(2c+1)       c(2c+1)     6c(2c+1)    6c    6c(2c+1)





              3c(3)         6(c-4)        5(2c+1)

            _________  -  _________  -  ___________  

             6c(2c+1)      6c(2c+1)      6c(2c+1)





                9c          6c-24         10c+5

            _________  -  _________  -  ___________  

             6c(2c+1)      6c(2c+1)      6c(2c+1)





                9c          -6c+24        -10c-5

            _________  +  _________  +  ___________  

             6c(2c+1)      6c(2c+1)      6c(2c+1)





             9c - 6c + 24 - 10c - 5

            _________________________  

                     6c(2c+1)  





                 -7c + 19

               _____________

                  6c(2c+1)  





                 -7c + 19

               _____________

                  12c^2+6c