SOLUTION: Differentiate by product rule....e to the power of (2t-5) sin t.... So e(2t-5)sin t

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Question 741692: Differentiate by product rule....e to the power of (2t-5) sin t.... So e(2t-5)sin t
Answer by Alan3354(69443) About Me  (Show Source):
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Differentiate by product rule....e to the power of (2t-5) sin t.... So e(2t-5)sin t
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f%28t%29+=+e%5E%282t-5%29%2Asin%28t%29
df%28t%29+=+2%2Ae%5E%282t-5%29%2Asin%28t%29+%2B+e%5E%282t-5%29%2Acos%28t%29