SOLUTION: Dr. Easy saw the scores from the MA-222 test and used the occasion to test the old adage that girls are smarter than boys on subjects tested by ACT. Assume the degrees of freedom f

Click here to see ALL problems on Probability-and-statistics

Question 74166: Dr. Easy saw the scores from the MA-222 test and used the occasion to test the old adage that girls are smarter than boys on subjects tested by ACT. Assume the degrees of freedom for this problem is 28. Dr. Easy did the arithmetic and found the value of the test statistic was 2.69 (alpha equals .05). What is the critical value (3 decimal places of significance)? If the mean of the boys score was lower than the mean of the girls score can she reject her null hypothesis? Yes or No.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Dr. Easy saw the scores from the MA-222 test and used the occasion to test the old adage that girls are smarter than boys on subjects tested by ACT. Assume the degrees of freedom for this problem is 28. Dr. Easy did the arithmetic and found the value of the test statistic was 2.69 (alpha equals .05). What is the critical value (3 decimal places of significance)? If the mean of the boys score was lower than the mean of the girls score can she reject her null hypothesis? Yes or No.
--------
Testing "girls are smarter" makes it a one-tail test.
With alpha = 0.05 the critical value is 1.645
-------
If the mean of the boys score was lower than the mean of the girls score can she reject her null hypothesis? Yes or No.
The hypotheses would be
Ho: u(girls)<=u(boys)
Ha: u(girls)>u(boys)
She should reject the null hypothesis if the mean of the boys score was lower
than the mean of the girls score.
==========
Cheers,
Stan H.