SOLUTION: Dear Sir/Madam, I'm struggling with absolute value equation of this type: 5|x+3|-2|x+1|=4 This is what I have tried so far: Case 1: 5(x+3)-2(x+1)=4 5x+15-2

Algebra ->  Absolute-value -> SOLUTION: Dear Sir/Madam, I'm struggling with absolute value equation of this type: 5|x+3|-2|x+1|=4 This is what I have tried so far: Case 1: 5(x+3)-2(x+1)=4 5x+15-2      Log On


   

Question 741657: Dear Sir/Madam,
I'm struggling with absolute value equation of this type:
5|x+3|-2|x+1|=4
This is what I have tried so far:
Case 1: 5(x+3)-2(x+1)=4
5x+15-2x-2=4
3x+13=4
3x=-9
x=-3
Case 2: -5(x+3)-2(x+1)=4
-5x-15-2x-2=4
-7x-17=4
-7x=21
x=-3
Therefore: x=-3
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Good start BUT not thorough enough.

Case: x%2B3%3E=0 and x%2B1%3E=0
5%28x%2B3%29-2x-2=4
.
find x=-3

Case: x%2B3%3C0 and x%2B1%3C0
-5%28x%2B3%29%2B2%28x%2B1%29=4
.
x=-3

Case: x%2B3%3E=0 and x%2B1%3C0
5%28x%2B3%29%2B2%28x%2B1%29=4
5x%2B15%2B2x%2B2=4
7x%2B17=4
7x=4-17
.
x=-%2813%2F7%29

Case: x%2B3%3C0 and x%2B1%3E=0
-5%28x%2B3%29-2%28x%2B1%29=4
.
x=-3

Solutions: x+=+-3 or x=-%2813%2F7%29