SOLUTION: Jackie has coffee that sells for $9 per pound and coffee that sells for $4 per pound. How many pounds of each must be mixed to get 20 pounds that sells for $8.25 per pound?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Jackie has coffee that sells for $9 per pound and coffee that sells for $4 per pound. How many pounds of each must be mixed to get 20 pounds that sells for $8.25 per pound?      Log On


   

Question 74147: Jackie has coffee that sells for $9 per pound and coffee that sells for $4 per pound. How many pounds of each must be mixed to get 20 pounds that sells for $8.25 per pound?
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Jackie has coffee that sells for $9 per pound and coffee that sells for $4 per pound. How many pounds of each must be mixed to get 20 pounds that sells for $8.25 per pound?
Let the amount of the $9 coffee be:x
Let the amount of the $4 coffee be:y
Then x+y=20
If we solve this for y, the y=20-x is the amount of the $4 coffee.
Cost=amount*(cost/amount)
so the cost of the $9 coffee is: 9x
Then the cost of the $4 coffee is: 4y or 4(20-x)
The total cost is: 8.25(20)
Problem to solve:
9x+4(20-x)=8.25(20)
9x+80-4x=165
5x+80=165
5x+80-80=165-80
5x=85
5x/5=85/5
x=17
The amount of $9 coffee is: x=17 lbs
The amount of $4 coffee is: y=20-x=20-17=3 lbs.
Happy Calculating!!!!