SOLUTION: Find all solutions in the interval [0, 2pi) Cos^2 (x/2) = cos^2 x
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Question 741244
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Find all solutions in the interval [0, 2pi)
Cos^2 (x/2) = cos^2 x
Answer by
lwsshak3(11628)
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Find all solutions in the interval [0, 2pi)
Cos^2 (x/2) = cos^2 x
2cos^2(x)-cos(x)-1=0
(2cos(x)+1)(cos(x)-1)=0
cos(x)=-1/2
x=2π/3, 4π/3 (in Q2 and Q3 where cos<0)
cos(x)-1=0
cos(x)=1
x=0