SOLUTION: 7(x+2a)^2+3a^2=5a(7x+23a)

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Question 741095: 7(x+2a)^2+3a^2=5a(7x+23a)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
7%28x%2B2a%29%5E2%2B3a%5E2=5a%287x%2B23a%29
7%28x%5E2%2B4ax%2B4a%5E2%29%2B3a%5E2=35ax%2B115a%5E2
7x%5E2%2B28ax%2B28a%5E2%2B3a%5E2=35ax%2B115a%5E2
7x%5E2%2B28ax%2B31a%5E2-35ax-115a%5E2=0
7x%5E2-7ax-84a%5E2=0
7x%5E2%2F7-7ax%2F7-84a%5E2%2F7=0
x%5E2-ax-12a%5E2=0....write -ax as 3ax-4ax

x%5E2%2B3ax-4ax-12a%5E2=0....group
%28x%5E2%2B3ax%29-%284ax%2B12a%5E2%29=0...factor

x%28x%2B3a%29-4a%28x%2B3a%29=0
%28x-4a%29%28x%2B3a%29=0
solutions:
if %28x-4a%29=0 => x=4a
if %28x%2B3a%29=0 => x=-3a