You can
put this solution on YOUR website! log(3m-5) + log(m) = log(2)
Use rule: log(A) + log(B) = log(AB) on the
left side
log[(3m-5)·m] = log(2)
log[3m²-5m] = log(2)
Use rule: log(A) = log(B) is equivalent to A = B
3m²-5m = 2
can you solve that quadratic equation. If not
post again
m = -1/3, 2
The log of a negative number is not defined. When
we substitute -1/3 for m in
log(3m-5) + log(m) = log(2)
the left side is undefined.
So we discard -1/3.
Checking m = 2
log(3·2-5) + log(2) = log(2)
log(6-5) + log(2) = log(2)
log(1) + log(2) = log(2)
0 + log(2) = log(2)
log(2) = log(2)
So m = 2 is the only solution.
Edwin
