SOLUTION: Find the prob. of E = {(a, b): a>b} where a, b are scores of two dice ordered D1, D2, a being the score of D1 and b that of D2.

Algebra ->  Probability-and-statistics -> SOLUTION: Find the prob. of E = {(a, b): a>b} where a, b are scores of two dice ordered D1, D2, a being the score of D1 and b that of D2.       Log On


   

Question 740837: Find the prob. of E = {(a, b): a>b} where a, b are scores of two dice ordered D1, D2, a being the score of D1 and b that of D2.
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) About Me  (Show Source):
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If comes up 1, then there are zero ways that can be strictly less than . If comes up 2, then there is exactly 1 way that can be strictly less than D_2]. implies there are 2 ways, and so on. Total of 15 possibilities for . There are 36 possible combinations of 2 dice.

John

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Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the prob. of E = {(a, b): a>b} where a, b are scores of two dice ordered D1, D2, a being the score of D1 and b that of D2.
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Sketch a 6 by 6 array of pairs.
Count the pairs where column values are greater than row values.
Divide that count by 36 to get the probabilty of E.
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Cheers,
Stan H.