SOLUTION: find the smallest number that should be added to 10 so that it can be divisible by 21,45 and 33

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Question 740781: find the smallest number that should be added to 10 so that it can be divisible by 21,45 and 33
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
21,45 and 33
THE PRIME FACTORS ARE:
21=1*3*7
45=1*3*3*5
33=1*3*11
MULTIPLY ALL UNIQUE FACTORS:
1*3*3*5*7*11=3,465
10+X=3,465
X=3,465-10
X=3,455 ANS.