SOLUTION: Need help with this problem:
The mean time to complete a task for a group of employees is 5.3 seconds with a standard deviation of 1.6 seconds. If a random sample of 60 employee
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The mean time to complete a task for a group of employees is 5.3 seconds with a standard deviation of 1.6 seconds. If a random sample of 60 employee
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Question 740770: Need help with this problem:
The mean time to complete a task for a group of employees is 5.3 seconds with a standard deviation of 1.6 seconds. If a random sample of 60 employees is selected, what is the probability that the mean time for these employees is less than 5 seconds? Found 2 solutions by lynnlo, stanbon:Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! The mean time to complete a task for a group of employees is 5.3 seconds with a standard deviation of 1.6 seconds.
If a random sample of 60 employees is selected, what is the probability that the mean time for these employees is less than 5 seconds?
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z(5) = (5-5.3)/[1.6/sqrt(60)] = 1.4524
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P(x < 5) = P(z < 1.4524) = normalcdf(-100,1.4524) = 0.9268
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Cheers,
Stan H.
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