SOLUTION: Find the value of x where 201, x, 1089 are three consecutive terms in a geometric sequence.

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Question 74069: Find the value of x where 201, x, 1089 are three consecutive terms in a geometric sequence.
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
(201x)x=1089
201x^2-1089=0
using the quadratic equation
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
we get
x=(0+-sqrt[0^2-4*201*-1089])/2*201
x=(+-sqrt875556)/402
x=(+-935.71)/402
x=935.71/402
x=2.32764 answer
proof
201*2.32764=468
468*2.32764=1089