SOLUTION: Find the exact solution of 2sinx-1=cscx in the interval [0,360]

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Question 740602: Find the exact solution of 2sinx-1=cscx in the interval [0,360]
Answer by MoeWilder_(1) About Me  (Show Source):
You can put this solution on YOUR website!
2sin%28x%29+-1=csc+%28x%29
2sin%28x%29+-1=1%2Fsin+%28x%29
sin%28x%29%2A%282sin%28x%29-1%29+=%281%2Fsin+%28x%29%29+%2Asin+%28x%29
2sinē(x)-sin (x)=1
2sinē(x)-sin (x)-1=0
2sinē(x)-2sin (x)+1sin (x)-1=0
2sin%28x%29%28sin%28x%29-1%29 %2B1%28sin+%28x%29-1%29=0
2sin+%28x%29%2B1=0 sin+%28x%29-1=0
2sin+%28x%29=+-1 sin+%28x%29+=+1
sin+%28x%29=+-1%2F2 x+=+arcsin%281%29
x=+arcsin%28-1%2F2%29 x+=+90
x=210
also
+x=330