SOLUTION: please help explain this equation: find the vertex, focus, axis, directrix and latus rectum of the parabola x^2+y=6x-14. i found the vertex to = (3, -5) i am not sure how to

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: please help explain this equation: find the vertex, focus, axis, directrix and latus rectum of the parabola x^2+y=6x-14. i found the vertex to = (3, -5) i am not sure how to      Log On


   

Question 74051: please help explain this equation:
find the vertex, focus, axis, directrix and latus rectum of the parabola
x^2+y=6x-14.
i found the vertex to = (3, -5)
i am not sure how to find the rest..thanks for any help.
this is from a problem we were given in class
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+y=6x-14
y=-x^2-6x-14
+graph%28+300%2C+200%2C+-6%2C+5%2C+-20%2C+20%2C+y+=+-x%5E2+-6x+-14%29+ (graph 300x200 pixels, x from -6 to 5, y from -20 to 20, y = -x^2 -6x -14).