SOLUTION: Factor completely: 2x^2 – 18y^2

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Question 74042: Factor completely:
2x^2 – 18y^2

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
2%2Ax%5E2-18%2Ay%5E2
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Notice that there is a common factor of 2 in the coefficients (multipliers) of the two terms
x%5E2 and y%5E2%29. Pull the 2 out as a factor and the problem becomes:
.
2%2A%28x%5E2+-+9y%5E2%29
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Next notice that the term in the parentheses is the difference of 2 perfect squares. The
rule for this factor is that %28A%5E2+-+B%5E2+%29=+%28A+-+B%29%2A%28A+%2B+B%29
.
In the given problem, x corresponds to A and 3y corresponds to B. So to factor the terms in the
parentheses you only need to replace A by x and B by 3y to find that:
.
%28x%5E2+-+%283y%29%5E2%29+=+%28x+-+3y%29%2A%28x+%2B+3y%29
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Substituting the right wide of this into the problem results in:
.
2%2A%28x-3y%29%2A%28x%2B3y%29
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and that's the answer to the problem. You can check it by multiplying all three factors together
to see if the result is the same as the original problem.
.
Hope this helps you to understand. First look for common factors in the numbers and pull them
out. Then see how to factor what is left. Sometimes it is useful to know common factor
forms such as this one ... how to factor the difference between two perfect squares.