SOLUTION: I need to solve for x, and our teacher wants us to get the same base but I can't figure how to get 1/8 to equal 2 without changing the value. Help! 2^(3x-1)=(1/8)^x

Algebra ->  Radicals -> SOLUTION: I need to solve for x, and our teacher wants us to get the same base but I can't figure how to get 1/8 to equal 2 without changing the value. Help! 2^(3x-1)=(1/8)^x      Log On


   

Question 740283: I need to solve for x, and our teacher wants us to get the same base but I can't figure how to get 1/8 to equal 2 without changing the value. Help!
2^(3x-1)=(1/8)^x
Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
Given: 2%5E%283x-1%29=%281%2F8%29%5Ex

2%5E%283x-1%29=%282%5E%28-3%29%29%5Ex
2%5E%283x-1%29=2%5E%28-3x%29
The base is the same on both sides so the corresponding exponents must be equal.

3x-1=-3x
6x-1=0
6x=1
6x%2A%281%2F6%29=1%2A%281%2F6%29
x%2A%286%29%2A%281%2F6%29=1%2F6
x%2A1=1%2F6
highlight%28x=1%2F6%29