SOLUTION: x^2-4x-8y+2=0 i know it is a parabola but i do i put it into standard form

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Question 740130: x^2-4x-8y+2=0 i know it is a parabola but i do i put it into standard form
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form of a parabola's equation is generally expressed:
y+=+ax%5E2+%2B+bx+%2B+c
The role of 'a'
If a%3E+0, the parabola opens upwards
if a%3C+0, it opens downwards.
The axis of symmetry
The axis of symmetry is the line x+=+-b%2F2a


to put your parabola into standard form, solve for y

x%5E2-4x-8y%2B2=0+

x%5E2-4x%2B2=8y+

%281%2F8%29x%5E2-%284%2F8%29x%2B2%2F8=y+

y=%281%2F8%29x%5E2-%281%2F2%29x%2B1%2F4+

a=1%2F8=> a%3E+0, the parabola opens upwards

The vertex form of a parabola's equation is generally expressed as :
y=+a%28x-h%29%5E2%2Bk
(h,k) is the vertex
in vertex form will be:
y=+a%28x-h%29%5E2%2Bk
y=%28%281%2F8%29x%5E2-%281%2F2%29x%2B______%29%2B1%2F4+....complete the square

y=%281%2F8%29%28x-2%29%5E2-1%2F4
(h=2,k=-1%2F4) is the vertex

+graph%28+600%2C+600%2C+-5%2C+10%2C+-5%2C+10%2C%281%2F8%29x%5E2-%281%2F2%29x%2B1%2F4%29+