SOLUTION: the length of a rectangle is three times as long as the width. If each side is increased by 6, the area of the new rectangle is 156 more than the area of the original rectangle. Wh

Algebra ->  Rectangles -> SOLUTION: the length of a rectangle is three times as long as the width. If each side is increased by 6, the area of the new rectangle is 156 more than the area of the original rectangle. Wh      Log On


   

Question 739952: the length of a rectangle is three times as long as the width. If each side is increased by 6, the area of the new rectangle is 156 more than the area of the original rectangle. What are the dimensions of the new rectangle?
Answer by lwsshak3(11628) About Me  (Show Source):
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the length of a rectangle is three times as long as the width. If each side is increased by 6, the area of the new rectangle is 156 more than the area of the original rectangle. What are the dimensions of the new rectangle?
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let x=width of original rectangle
3x=length of original rectangle
Area of original rectangle=3x*x=3x^2
x+6=width of new rectangle
3x+6=length of new rectangle
Area of new rectangle=(x+6)(3x+6)=3x^2+24x+36
area of original rectangle+156=area of new rectangle
3x^2+156=3x^2+24x+36
24x=120
x=5
x+6=11
3x+6=21
width of new rectangle=11
length of new rectangle=21