SOLUTION: Solve for x. log(base2)(x - 6) + log(base2)(x - 4) = log(base2)x
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Question 739894
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Solve for x.
log(base2)(x - 6) + log(base2)(x - 4) = log(base2)x
Answer by
lwsshak3(11628)
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Solve for x.
log(base2)(x - 6) + log(base2)(x - 4) = log(base2)x
***
x=(x-6)(x-4)
x=x^2-10x+24
x^2-11x+24=0
(x-8)(x-3)=0
x=8
or
x=3(reject, (x-6)>0)