SOLUTION: 4) For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula,A=P(1+r/n)^nt , let r = 10%, P = 1,

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: 4) For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula,A=P(1+r/n)^nt , let r = 10%, P = 1,      Log On


   



Question 73986: 4) For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula,A=P(1+r/n)^nt , let r = 10%, P = 1, and n = 1 and give the coordinates (t, A) for the points where t = 0, 1, 2, 3, 4. Round your answer to the hundredth's place.
a) Show coordinates in this space


Show work in this space


b) Show graph here

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
4) For a fixed rate, a fixed principal amount, and a fixed compounding cycle, the return is an exponential function of time. Using the formula,A=P(1+r/n)^nt , let r = 10%, P = 1, and n = 1 and give the coordinates (t, A) for the points where t = 0, 1, 2, 3, 4. Round your answer to the hundredth's place.
a) Show coordinates in this space
(0,1); (1,1.1); (2,1.21); (3,1.33); (4,1.46)

Show work in this space
r=.10 P=1 n=1
A=1%281%2B.10%2F1%29%5E%281t%29
A=%281%2B.10%29%5Et
A=%281.1%29%5Et
for t=0
A=%281.1%29%5E0
A=1 (0,1)
for t=1
A=%281.1%29%5E1
A=1.1 (1,1.1)
for t=2
A=%281.1%29%5E2
A=1.21 (2,1.21)
for t=3
A=%281.1%29%5E3
A=1.331 (3,1.33)
for t=4
A=%281.1%29%5E4
A=1.4641 (4,1.46)
:
b) Show graph here
graph%28300%2C200%2C-10%2C10%2C-3%2C10%2C%281.1%29%5Ex%29
Happy Calculating!!!!