SOLUTION: Working together Tumelo and Jan can sand a floor in five-eighths of the time that it takes Jan to sand it by himself.Jan takes 6 hours to sand the floor alone.How long does it ta

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Question 739738:
Working together Tumelo and Jan can sand a floor in five-eighths of the time that it takes Jan to sand it by himself.Jan takes 6 hours to sand the floor alone.How long does it take Tumelo to sand the floor by himself?
Found 2 solutions by ankor@dixie-net.com, checkley79:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Working together Tumelo and Jan can sand a floor in five-eighths of the time that it takes Jan to sand it by himself.
Jan takes 6 hours to sand the floor alone.
How long does it take Tumelo to sand the floor by himself?
:
let t = T's time alone
:
It says,"Tumelo and Jan can sand a floor in five-eighths of the time that it takes Jan who take 6 hrs by himself" therefore:
5%2F8 * 6 = 3.75 hrs working together
:
let the completed job = 1
:
A shared work equation,
:
3.75%2F6 + 3.75%2Ft = 1
multiply by 6t
3.75t + 3.75(6) = 6t
3.75t + 22.5 = 6t
22.5 = 6t - 3.75t
22.5 = 2.25t
t = 22.5/2.25
t = 10 hr is T's time alone
:
:
See if that checks out
3.75%2F6 + 3.75%2F10 =
.625 + .375 = 1

Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
J=8 HOURS
T=X HOURS
1/8+1/X=1/(5/8*8)
(X+8)/8X=1/5 CROSS MULTIPLY.
8X=5(X+8)
8X=5X+40
8X-5X=40
3X=40
X=40/3
X=13 1/3 HOURS FOR TUMELO WORKING ALONE.
PROOF:
1/8+1/(40/3)=1/(5/8*8)
1/8+3/40=1/5
(5+3)/40=1/5
8/40=1/5
1/5=1/5