SOLUTION: You need a 15% alcohol solution. On hand, you have a 195 mL of a 35% alcohol mixture. How much pure water will you need to add to obtain the desired solution? You will need mL

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: You need a 15% alcohol solution. On hand, you have a 195 mL of a 35% alcohol mixture. How much pure water will you need to add to obtain the desired solution? You will need mL       Log On

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Question 739687: You need a 15% alcohol solution. On hand, you have a 195 mL of a 35% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
You will need
mL of pure water
to obtain
mL of the desired 15% solution.
idk how to do this;(

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +w+ = ml of pure water to be added
+.35%2A195+=+68.25+ ml of alcohol in 35% mixture
----------------
+68.25+%2F+%28+195+%2B+w+%29+=+.15+
+68.25+=+.15%2A%28+195+%2B+w+%29+
+68.25+=+29.25+%2B+.15w+
+.15w+=+39+
+w+=+260+
260 ml of pure water to be should be added
check:
+68.25+%2F+%28+195+%2B+w+%29+=+.15+
+68.25+%2F+%28+195+%2B+260+%29+=+.15+
You can check it