SOLUTION: I have spent about an hour on this mixture problem and can't seem to get the correct formula. Please help. A service station manager is going to blend high octane gasoline wort

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Question 73967: I have spent about an hour on this mixture problem and can't seem to get the correct formula. Please help.
A service station manager is going to blend high octane gasoline worth 63 cents per gallon with low octane gasoline with 51 cents per gallon. If the resulting mixture is 210 gallons of gasoline, express the total value V of the mixture (in cents) as a function of the number of gallons x of high octane gasoline used.
Answer by ffc_01(9) About Me  (Show Source):
You can put this solution on YOUR website!
y = # gal of high octane
x = # gal of low octane
y is worth .63 per gal
x is worth .51 per gal
mixture = 210 gal
y + x = 210
.63y + .51x = V
To write this as a function of V we need to eliminate one of the variables.
From the first equation, we get...
y = 210 - x
Lets substitute that into the second equation. V is a function of x.
V(x) = .63(210 - x) + .51x
= .63(210) - .63x +.51x
= 132.3 - .12x