SOLUTION: Can you please help me round angle measures to the nearest degree and side measures to the nearest tenth for this problem: One side of a triangular garden is 42.0 feet. The angles

Algebra ->  Triangles -> SOLUTION: Can you please help me round angle measures to the nearest degree and side measures to the nearest tenth for this problem: One side of a triangular garden is 42.0 feet. The angles       Log On


   

Question 73952: Can you please help me round angle measures to the nearest degree and side measures to the nearest tenth for this problem: One side of a triangular garden is 42.0 feet. The angles on each end of this side measure 66 degrees and 82 degrees. Find the length of fence needed to enclose the garden. (Law of Sines)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Can you please help me round angle measures to the nearest degree and side
measures to the nearest tenth for this problem:
:
One side of a triangular garden is 42.0 feet. The angles on each end of this side measure 66 degrees and 82 degrees. Find the length of fence needed to
enclose the garden. (Law of Sines)
:
Draw a triangle:
A = 66 degrees, B = 82 degrees, c = 42 ft; Angle C = 180 - 66 - 82 = 32 degrees
:
Low of sines:
sinA%2Fa = sinB%2Fb = sinC%2Fc
:
sin%2866%29%2Fa = sin%2882%29%2Fb = sin%2832%29%2F42
:
Find the value for: sin%2832%29%2F42
.52992/42 = .012617
:
sinA%2Fa = .012617
sin%2866%29%2Fa = .012617
.9525%2Fa = .012617
a = .9525%2F.012617
a = 72.4 ft
:
sinB%2Fb = .012617
sin%2882%29%2Fb = .012617
.990268%2Fb = .012617
b = .990269%2F.012617
b = 78.48 ft
:
72.4 + 78.5 + 42 = 192.9 ft of fence required
:
This is one way to do it. Check my math