SOLUTION: Please help me solve this problem. How many ways are there to pair off eight women at the dance with eight of these 12 men? This is what I have so far, but

Algebra ->  Permutations -> SOLUTION: Please help me solve this problem. How many ways are there to pair off eight women at the dance with eight of these 12 men? This is what I have so far, but       Log On


   



Question 739481: Please help me solve this problem.
How many ways are there to pair off eight women at the dance with eight of these 12 men?
This is what I have so far, but I think I have it wrong. Thank you in advance.
=n∁r
=12C8
= 12!
4! 8!
= 12*11*10*9
4*3*2*1
=495 combinations

Answer by Ed McCravy(3) About Me  (Show Source):
You can put this solution on YOUR website!
This is permutation problem, not a combination problem.

Here is why:

The women are W1, W2, W3, W4, W5, W6, W7, W8

Think of them lined up in that order. Not only do you
just choose 8 of the 12 men to dance with these 8 women,
but you have to place them in a certain order with these
women.

So the answer is 12P8, or 19,958,400.

[Your answer would have been correct if they weren't dancing
but were just forming a committee of 16 with 8 men and 8 women.]

Edwin