SOLUTION: ankita travel 14 km to home partially by rickshaw AND BY BUS SHE TAKES 1 2 HR IF SHE TRAVELS BY RICKSHAW AND THE REMAING DISTANCE BY BUS ON OTHER HAND IF SHE TRAVELS 4 KM BY RICKSH

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: ankita travel 14 km to home partially by rickshaw AND BY BUS SHE TAKES 1 2 HR IF SHE TRAVELS BY RICKSHAW AND THE REMAING DISTANCE BY BUS ON OTHER HAND IF SHE TRAVELS 4 KM BY RICKSH      Log On


   



Question 739216: ankita travel 14 km to home partially by rickshaw AND BY BUS SHE TAKES 1 2 HR IF SHE TRAVELS BY RICKSHAW AND THE REMAING DISTANCE BY BUS ON OTHER HAND IF SHE TRAVELS 4 KM BY RICKSHAW AND REMAING DISTANCE BY BUS SHE TAKES 9 MINUTES LONGER



Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Will try to make sense of this.
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Ankita travel 14 km home, partially by rickshaw and by bus.
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She takes 1%2F2 hr if is she travels 4 km by Rickshaw and takes the remaining distance by by bus.
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On the other hand, if she travels 10 km by rickshaw, and the remaining distance by bus, she takes 9 min longer.
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Assume you want to find the speed of the rickshaw and speed of the bus.
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let r = speed of the rickshaw
let b = speed of the bus
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Write an time equation for the 1st statement (time = dist/speed):
"She takes 1%2F2 hr if is she travels 4 km by Rickshaw and takes the remaining distance by by bus."
4%2Fr + 10%2Fb = 1%2F2
multiply equation by 2rb, to get rid of the denominators
2rb*4%2Fr + 2rb*10%2Fb = 2rb*1%2F2
cancel the denominators
8b + 20r = rb
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Write a time equation for the 2nd statement (time = dist/speed):
"if she travels 10 km by rickshaw, and the remaining distance by bus, she takes 9 min longer."
10%2Fr + 4%2Fb = 30 + 9
10%2Fr + 4%2Fb = 39
change 39 min to hr (we're finding the speed in km/hr
10%2Fr + 4%2Fb = 39%2F60
10%2Fr + 4%2Fb = 13%2F20
multiply equation by 20rb, to get rid of the denominators
20rb*10%2Fr + 20rb*4%2Fb = 20rb*13%2F20
cancel the denominators
200b + 80r = 13rb
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multiply the first equation by 4, subtract from the above equation
200b + 80r = 13rb
32b + 80r = 4rb
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168b = 9rb
divide both sides by by b
168 = 9r
r = 168/9
r = 18.67 km/hr is the speed of the rickshaw (Is that possible?)
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Find the speed of the bus
8b + 20r = rb
8b + 20(18.67) = 18.67b
373.3 = 18.67b - 8b
373.3 = 10.67b
b = 373.3/10.67
b ~ 35 km/hr is the speed of the bus
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See if that checks out in the first statement, find the travel time of each
4%2F18.67 + 10%2F35 =
.214 + .286 = .5 hrs