SOLUTION: Find the exact value of sin^-1(-sqrt3/2).
a.2sin(4t)cos(2t)
b.2cos(4t)sin(2t)
c.2cos(4t)cos(2t)
d.2sin(4t)sin(2t)
Than you for you help
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Trigonometry-basics
-> SOLUTION: Find the exact value of sin^-1(-sqrt3/2).
a.2sin(4t)cos(2t)
b.2cos(4t)sin(2t)
c.2cos(4t)cos(2t)
d.2sin(4t)sin(2t)
Than you for you help
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Question 73916This question is from textbook
: Find the exact value of sin^-1(-sqrt3/2).
a.2sin(4t)cos(2t)
b.2cos(4t)sin(2t)
c.2cos(4t)cos(2t)
d.2sin(4t)sin(2t)
Than you for you help
You can put this solution on YOUR website! Find the exact value of sin^-1(-sqrt3/2).
a.2sin(4t)cos(2t)
b.2cos(4t)sin(2t)
c.2cos(4t)cos(2t)
d.2sin(4t)sin(2t)
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You want the angle whose sine is (-sqrt3)/2
Draw the angle:
y=-sqrt3
r= 2
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That angle is in the 4th quadrant.
The reference angle is 60 degrees.
That is the angle theta= 300 or theta = -60 degrees in the 4th Quadrant.
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Cheers,
Stan H.
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