SOLUTION: Running at an average rate of 6 meters per
second, a sprinter ran to the end of a track. The sprinter then
jogged back to the starting point at an average rate of 2 meters
per s
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second, a sprinter ran to the end of a track. The sprinter then
jogged back to the starting point at an average rate of 2 meters
per s
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Question 739132: Running at an average rate of 6 meters per
second, a sprinter ran to the end of a track. The sprinter then
jogged back to the starting point at an average rate of 2 meters
per second. The total time for the sprint and the jog back was
2 minutes 40 seconds. Find the length of the track. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Running at an average rate of 6 meters per second, a sprinter ran to the end of a track.
The sprinter then jogged back to the starting point at an average rate of 2 meters per second.
The total time for the sprint and the jog back was 2 minutes 40 seconds.
Find the length of the track.
:
Since we are dealing in m/sec, change 2 min 40 sec to 160 seconds
:
let d = the length of the track
:
Write a time equation; time = dist/speed
:
Sprint time + jog time = 2 min 40 sec + = 160
mult by 6 to clear the denominators
d + 3d = 6(160)
4d = 960
d = 240 meters is the length of the track
:
:
Check this:
240/6 = 40 sec
240/2 = 120 sec
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tot time 160 sec
