SOLUTION: From her house, Ann drove to her grandmother's at an average speed of 60 miles per hour. She returned over the Same route at average speed of 45 miles per hour. If ann spent 7 hour

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Question 738955: From her house, Ann drove to her grandmother's at an average speed of 60 miles per hour. She returned over the Same route at average speed of 45 miles per hour. If ann spent 7 hours traveling, how many miles is Ann's grandmother's house from her house?
I have no idea what to do?

Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Two things come to mind while just reading the description one time:
(rate)*(time)=(distance), and total time traveling was 7 hours.

Going to Granmother's ----- 60%2Au=d
u is time and d is distance. We know neither.
Also, u=d%2F60

Returning from Grandmother's----- 45%2Av=d
v is time traveling and d is distance. We know neither.
Also, v=d%2F45

...but we know that d is the same in each equation, being distance to grandmother's house.

Use the time travel information give, that 7 hours.
u%2Bv=7
highlight%28d%2F60%2Bd%2F45=7%29
SOLVE for d.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +t+ = her time in hrs for the 1st trip
+7-t+ = her time for the trip back
Let +d+ = distance to grandmother's house
----------------
(1) +d+=+60t+
(2) +d+=+45%2A%28+7+-+t+%29+
--------------------
Substitute (1) into (2)
(2) +60t+=+45%2A%28+7+-+t+%29+
(2) +60t+=+315+-+45t+
(2) +105t+=+315+
(2) +t+=+3++
and
(1) +d+=+60t+
(1) +d+=+60%2A3+
(1) +d+=+180+
The distance to grandmother's house is 180 mi
check:
(2) +d+=+45%2A%28+7+-+t+%29+
(2) +180+=+45%2A%28+7+-+3+%29+
(2) +180+=+45%2A4+
(2) +180+=+180+
OK