SOLUTION: A ball is thrown downward from the top of a 180 foot building with an initial velocity of 20 feet per second. The height of the ball h after t seconds is given by the equation h=-1

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Question 738944: A ball is thrown downward from the top of a 180 foot building with an initial velocity of 20 feet per second. The height of the ball h after t seconds is given by the equation h=-16t^2-20t+180. How long after the ball is thrown will it be 50 feet from the ground? Round the result to the nearest tenth of a second.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
50=-16t^2-20t+180
t=2.29315
t=2.3