SOLUTION: Find three consecutive even integers such that twice the second plus 3 times the third is 7 times the first.

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Question 738686: Find three consecutive even integers such that twice the second plus 3 times the third is 7 times the first.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

2x + 3(x+2) = 7(x-2)
2x + 3x + 6 = 7x - 14
20 = 2x
x = 10

The integers are 8, 10, and 12.