SOLUTION: 10c^2 + 25c – 6c – 15 factor by grouping

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Question 738376: 10c^2 + 25c – 6c – 15 factor by grouping
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

10c%5E2%2B25c-6c-15 Start with the given expression


%2810c%5E2%2B25c%29%2B%28-6c-15%29 Group the terms in two pairs


5c%282c%2B5%29-3%282c%2B5%29 Factor out the GCF 5c out of the first group. Factor out the GCF -3 out of the second group


%285c-3%29%282c%2B5%29 Since we have the common term 2c%2B5, we can combine like terms


So 10c%5E2%2B25c-6c-15 factors to %285c-3%29%282c%2B5%29


In other words, 10c%5E2%2B25c-6c-15=%285c-3%29%282c%2B5%29