SOLUTION: find two consecutive positive integers such that the square of the first decrease by 17 equals 4 times the second

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Question 738339: find two consecutive positive integers such that the square of the first decrease by 17 equals 4 times the second
Answer by CubeyThePenguin(3113) About Me  (Show Source):
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consecutive positive integers: x, (x+1)

x^2 - 17 = 4(x + 1)
x^2 - 17 = 4x + 4
x^2 - 4x - 21 = 0
(x - 7)(x + 3) = 0
x = 7, x = -3

The integers are positive, so the integers are 7 and 8.