You can put this solution on YOUR website! ...move to the left
......now you have equation of parabola in vertex form where (,) are vertex coordinates, and coefficient
If , the parabola opens upwards
if , it opens downwards; since your => and parabola opens downwards
to graph this function, you need several points to plot and draw a parabola through
table:
let first point be vertex
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You can put this solution on YOUR website! graph of the function -2(x - 1)^2 = y + 5
This is an equation of a parabola that opens downward:
Its standard (vertex) form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex. A is a coefficient that affects the slope or steepness of the curve.
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For given equation: -2(x - 1)^2 = y + 5
rearrange terms to standard form:
A=-2
vertex: (1,5)
axis of symmetry: x=1
y-intercept
set x=0
y=-2+5=3
see graph below:
(