Question 737805: suppose you drive 100 mile home for fall break. your return trip took 30 minutes less because you drive 10 mph faster Answer by Ed Parker(21) (Show Source):
You can put this solution on YOUR website! suppose you drive 100 mile home for fall break. your return trip took 30 minutes less because you drive 10 mph faster. What was your rate on the return trip?
distance rate time=distance/rate
going home 100 x 100/x
returning 100 x+10 100/(x+10)
hour
Solve that and get x=40 mph going home and therefore the returning rate
is x+10 or 40+10 = 50 mph.
Edwin
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