SOLUTION: Mr. Carmona has a total of $1.05 in nickels and dimes. If he had three more nickels, then he'd have four times as many nickels as dimes. Find the number of nickels and dimes.

Algebra ->  Test -> SOLUTION: Mr. Carmona has a total of $1.05 in nickels and dimes. If he had three more nickels, then he'd have four times as many nickels as dimes. Find the number of nickels and dimes.       Log On


   



Question 737512: Mr. Carmona has a total of $1.05 in nickels and dimes. If he had three more nickels, then he'd have four times as many nickels as dimes. Find the number of nickels and dimes.
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!

.05N+.10D=1.05
N+3=4D
N=4D-3
.05(4D-3)+.10D=1.05
.20D-.15+.10D=1.05
.30D=1.05+15
.30D=1.20
D=1.20/.30
D=4 NUMBER OF DIMES.
N+3=4*4
N+3=16
N=16-3
N=13 NUMBER OF NICKLES.
PROOF:
.05*13+.10*4=1.05
.65+.40=1.05
1.05=1.05