SOLUTION: How do you solve and graph: /c-4/ > 1 The c-4 is in absolute value lines. Thank you!

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Question 73747: How do you solve and graph:
/c-4/ > 1
The c-4 is in absolute value lines.
Thank you!

Found 2 solutions by jim_thompson5910, bucky:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
abs%28c-4%29%3E1Since the absolute value of a positive and a negative number is that same number but always positive, you can write an absolute value expression like abs%28x%29=a as this x=a and x=-a So this problem can be written as
-1%3Ec-4%3E1Now we can solve for c
-1%2B4%3Ec%3E1%2B4
3%3Ec%3E5
Which finally looks like
c%3C3_and_c%3E5
graph%28+300%2C+200%2C+-1%2C+10%2C+-10%2C+10%2C+abs%28x-4%29%2C1%29+
For the graph you would shade above y=1 and below y=abs%28x-4%29 (we let c=x). So shade in between the green and the red lines; however, don't shade in the middle triangle, since the abs%28x-4%29 is not greater than 1 in this region.

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
.
abs%28c-4%29%3E1
.
solve and graph
.
One way to do absolute value problems is to solve them as two separate problems. For the
first problem, remove the absolute value signs and solve:
.
+(c-4)>1
.
You can treat this just as you would and equation ... except for one difference. That difference
is that if you have to multiply or divide both sides by a negative number, you must then
reverse the direction of the inequality sign. Don't forget that.
.
Now back to solving:
.
+(c-4)>1
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The parentheses are preceded by a plus sign so you can just remove them and the inequality
becomes:
.
+c - 4 > 1
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Just as you would in an equation, eliminate the -4 on the left side by adding 4 to both
sides to get:
.
+c > 5
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That's the first limit on the value of c ... it must be greater than +5.
.
Now, on to the second equation. We do the same thing as before ... remove the absolute
value signs, except this time we put a minus sign in front of the quantity that was inside
the absolute value signs. When you do this you have:
.
-(c-4)>1
.
Because the quantity is preceded by a negative sign, when you remove the parentheses
you must change the sign of every term that was inside the parentheses. When you do
that the inequality becomes:
.
-c + 4 >1
.
We need to solve this for +c. Let's begin by eliminating the +4 on the left side by
subtracting 4 from both sides. This causes the inequality to become:
.
-c > -3
.
To change the equation so that the left side is +c, multiply both sides by negative 1.
And when you do, do NOT forget to reverse the direction of the inequality sign to get:
.
+c < +3
.
This tells us that c must be less than +3
.
Combined, the two restrictions are that c can be any number less than 3 and it can also
be any number greater than 5. But it cannot be either 3 or 5 or any number between those
two values.
.
Let's check that out with a trio of trials. Start with the problem:
.
abs%28c-4%29%3E1
.
Let's set c equal to zero. That's a number less than +3 so it should work. When you substitute
0 for c you get:
.
abs%280-4%29%3E1 which simplifies to:
.
abs%28-4%29%3E1 and since abs%28-4%29+=+%2B4 we get +4 > 1. That works!
.
Now let's set c equal to 4. That should NOT work. Substitute 4 for c and get:
.
abs%284-4%29%3E1 this obviously becomes:
.
abs%280%29%3E1 and the absolute value of 0 is 0. Obviously 0 > 1 is NOT true so numbers
between 3 and 4 probably all need to be excluded.
.
Finally try c = 6. That is greater than +5 and should work. Substitute +5 for c and get:
.
abs%286-4%29%3E1 which becomes abs%286-4%29%3E1 and simplifies to abs%282%29%3E1.
At this point it is obvious that 2 > 1 is true and that adds to the likelihood that numbers
greater than 5 will work.
.
We have a good solution!
.
To graph, just make a number line and put dots at +3 and +5. Exclude those dots and shade
the number line from just to the left of +3 all the way to the left and from just to
the right of +5 all the way to the right. c can take any value in the shaded region.
.
Hope this shows you a way to work absolute value inequalities. Remember the two different
equations to solve (one by using the absolute value quantity with a + sign and the other
by using that quantity with a minus sign preceding it), the need to reverse the direction of
the inequality sign if multiplying or dividing both sides by a negative number, and to
always solve for the positive value of the variable. The rest is just algebraic manipulation.
.
Hope this works for you.
.