SOLUTION: A man is 32 years older than his son,ten years ago he was 3 times as old as his son.find the present age of each.

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Question 737416: A man is 32 years older than his son,ten years ago he was 3 times as old as his son.find the present age of each.
Answer by Susan-math(40) About Me  (Show Source):
You can put this solution on YOUR website!
Let m=man's age
Then s =son's age = m-32
Man's age ten years ago was m-10
Son's age ten years ago was m - 32 -10=m-42
But we also know man 10 years ago = 3* son 10 years ago
So m-10=3%2A%28m-42%29
Distribute and simplify:
M
m-10=3m-3%2842%29=3m-126
m-10=3m-126
Subtract m from both sides
-10=2m-126
Add 126 to both sides
116=2m and divide by 2 on both sides to get m =58.
So the man is now 58 years old. Going to the top, we find his son is 32 years younger, so his son is 58-32=26.
To check, go back ten years: the man was 48 and his son was 16 and 48=3*16.